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256104043 = 1319700311
BaseRepresentation
bin11110100001111…
…01011001101011
3122211220102200221
433100331121223
51011030312133
641225110511
76226564006
oct1720753153
9584812627
10256104043
11121622838
1271928437
134109bb70
142602853d
151773ca2d
hexf43d66b

256104043 has 4 divisors (see below), whose sum is σ = 275804368. Its totient is φ = 236403720.

The previous prime is 256103957. The next prime is 256104049. The reversal of 256104043 is 340401652.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 256104043 - 29 = 256103531 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 256103999 and 256104017.

It is not an unprimeable number, because it can be changed into a prime (256104049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9850143 + ... + 9850168.

It is an arithmetic number, because the mean of its divisors is an integer number (68951092).

Almost surely, 2256104043 is an apocalyptic number.

256104043 is a deficient number, since it is larger than the sum of its proper divisors (19700325).

256104043 is a wasteful number, since it uses less digits than its factorization.

256104043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19700324.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 256104043 is about 16003.2510134660. The cubic root of 256104043 is about 635.0464289114.

Adding to 256104043 its reverse (340401652), we get a palindrome (596505695).

The spelling of 256104043 in words is "two hundred fifty-six million, one hundred four thousand, forty-three".

Divisors: 1 13 19700311 256104043