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2561044034255 = 57149491091857
BaseRepresentation
bin100101010001001010000…
…111101011001011001111
3100001211111120011210201012
4211101022013223023033
5313430004233044010
65240305525435435
7353013026052650
oct45211207531317
910054446153635
102561044034255
118a8150655773
1235442056bb7b
13157675526375
148bd53097527
1546942d42005
hex2544a1eb2cf

2561044034255 has 16 divisors (see below), whose sum is σ = 3535861377600. Its totient is φ = 1744358272512.

The previous prime is 2561044034251. The next prime is 2561044034293. The reversal of 2561044034255 is 5524304401652.

2561044034255 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 2561044034255 - 22 = 2561044034251 is a prime.

It is a super-2 number, since 2×25610440342552 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2561044034251) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 245540714 + ... + 245551143.

It is an arithmetic number, because the mean of its divisors is an integer number (220991336100).

Almost surely, 22561044034255 is an apocalyptic number.

2561044034255 is a deficient number, since it is larger than the sum of its proper divisors (974817343345).

2561044034255 is a wasteful number, since it uses less digits than its factorization.

2561044034255 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 491092018.

The product of its (nonzero) digits is 576000, while the sum is 41.

The spelling of 2561044034255 in words is "two trillion, five hundred sixty-one billion, forty-four million, thirty-four thousand, two hundred fifty-five".

Divisors: 1 5 7 35 149 745 1043 5215 491091857 2455459285 3437642999 17188214995 73172686693 365863433465 512208806851 2561044034255