2561127048737 has 4 divisors (see below), whose sum is σ = 2561172807360. Its totient is φ = 2561081290116.

The previous prime is 2561127048679. The next prime is 2561127048787. The reversal of 2561127048737 is 7378407211652.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2561127048737 - 2¹⁴ = 2561127032353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2561127048787) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22795253 + ... + 22907330.

It is an arithmetic number, because the mean of its divisors is an integer number (640293201840).

Almost surely, 2^{2561127048737} is an apocalyptic number.

It is an amenable number.

2561127048737 is a deficient number, since it is larger than the sum of its proper divisors (45758623).

2561127048737 is an equidigital number, since it uses as much as digits as its factorization.

2561127048737 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45758622.

The product of its (nonzero) digits is 3951360, while the sum is 53.

The spelling of 2561127048737 in words is "two trillion, five hundred sixty-one billion, one hundred twenty-seven million, forty-eight thousand, seven hundred thirty-seven".