Base | Representation |
---|---|
bin | 1011101001011100101011… |
… | …10111001011001101000001 |
3 | 10100200121200011220101200120 |
4 | 11310232111313023031001 |
5 | 11324122222442130131 |
6 | 130250345132410453 |
7 | 5252336014642611 |
oct | 564562567131501 |
9 | 110617604811616 |
10 | 25613404255041 |
11 | 8185646a64319 |
12 | 2a58071316a29 |
13 | 113a445078455 |
14 | 6479a41a4a41 |
15 | 2e63e40cb496 |
hex | 174b95dcb341 |
25613404255041 has 8 divisors (see below), whose sum is σ = 34795568044800. Its totient is φ = 16753421650992.
The previous prime is 25613404255009. The next prime is 25613404255051. The reversal of 25613404255041 is 14055240431652.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 25613404255041 - 25 = 25613404255009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25613404254984 and 25613404255002.
It is not an unprimeable number, because it can be changed into a prime (25613404255051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80545296241 + ... + 80545296558.
It is an arithmetic number, because the mean of its divisors is an integer number (4349446005600).
Almost surely, 225613404255041 is an apocalyptic number.
It is an amenable number.
25613404255041 is a deficient number, since it is larger than the sum of its proper divisors (9182163789759).
25613404255041 is a wasteful number, since it uses less digits than its factorization.
25613404255041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161090592855.
The product of its (nonzero) digits is 576000, while the sum is 42.
Adding to 25613404255041 its reverse (14055240431652), we get a palindrome (39668644686693).
The spelling of 25613404255041 in words is "twenty-five trillion, six hundred thirteen billion, four hundred four million, two hundred fifty-five thousand, forty-one".
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