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25613404255041 = 353161090592799
BaseRepresentation
bin1011101001011100101011…
…10111001011001101000001
310100200121200011220101200120
411310232111313023031001
511324122222442130131
6130250345132410453
75252336014642611
oct564562567131501
9110617604811616
1025613404255041
118185646a64319
122a58071316a29
13113a445078455
146479a41a4a41
152e63e40cb496
hex174b95dcb341

25613404255041 has 8 divisors (see below), whose sum is σ = 34795568044800. Its totient is φ = 16753421650992.

The previous prime is 25613404255009. The next prime is 25613404255051. The reversal of 25613404255041 is 14055240431652.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 25613404255041 - 25 = 25613404255009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25613404254984 and 25613404255002.

It is not an unprimeable number, because it can be changed into a prime (25613404255051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80545296241 + ... + 80545296558.

It is an arithmetic number, because the mean of its divisors is an integer number (4349446005600).

Almost surely, 225613404255041 is an apocalyptic number.

It is an amenable number.

25613404255041 is a deficient number, since it is larger than the sum of its proper divisors (9182163789759).

25613404255041 is a wasteful number, since it uses less digits than its factorization.

25613404255041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161090592855.

The product of its (nonzero) digits is 576000, while the sum is 42.

Adding to 25613404255041 its reverse (14055240431652), we get a palindrome (39668644686693).

The spelling of 25613404255041 in words is "twenty-five trillion, six hundred thirteen billion, four hundred four million, two hundred fifty-five thousand, forty-one".

Divisors: 1 3 53 159 161090592799 483271778397 8537801418347 25613404255041