Base | Representation |
---|---|
bin | 1110111010001110110… |
… | …0110101111111010111 |
3 | 220111011111111102220120 |
4 | 3232203230311333113 |
5 | 13144043233342101 |
6 | 313401245003023 |
7 | 24335423633421 |
oct | 3564354657727 |
9 | 814144442816 |
10 | 256149512151 |
11 | 996a57a37a5 |
12 | 41787b53473 |
13 | 1b202115790 |
14 | c57d41d811 |
15 | 69e2b36b36 |
hex | 3ba3b35fd7 |
256149512151 has 8 divisors (see below), whose sum is σ = 367804427760. Its totient is φ = 157630468992.
The previous prime is 256149512147. The next prime is 256149512167. The reversal of 256149512151 is 151215941652.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 256149512151 - 22 = 256149512147 is a prime.
It is a super-2 number, since 2×2561495121512 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (256149512131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3283968066 + ... + 3283968143.
It is an arithmetic number, because the mean of its divisors is an integer number (45975553470).
Almost surely, 2256149512151 is an apocalyptic number.
256149512151 is a deficient number, since it is larger than the sum of its proper divisors (111654915609).
256149512151 is a wasteful number, since it uses less digits than its factorization.
256149512151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6567936225.
The product of its digits is 108000, while the sum is 42.
The spelling of 256149512151 in words is "two hundred fifty-six billion, one hundred forty-nine million, five hundred twelve thousand, one hundred fifty-one".
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