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2561544001 = 13119553771
BaseRepresentation
bin1001100010101110…
…0000111101000001
320121111222220210001
42120223200331001
520221223402001
61102102440001
7120322523212
oct23053407501
96544886701
102561544001
1110a4a19a15
125b5a33001
1331a8ca113
141a42b1409
15eed36001
hex98ae0f41

2561544001 has 4 divisors (see below), whose sum is σ = 2581097904. Its totient is φ = 2541990100.

The previous prime is 2561543951. The next prime is 2561544023. The reversal of 2561544001 is 1004451652.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2561544001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2561544031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9776755 + ... + 9777016.

It is an arithmetic number, because the mean of its divisors is an integer number (645274476).

Almost surely, 22561544001 is an apocalyptic number.

It is an amenable number.

2561544001 is a deficient number, since it is larger than the sum of its proper divisors (19553903).

2561544001 is a wasteful number, since it uses less digits than its factorization.

2561544001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19553902.

The product of its (nonzero) digits is 4800, while the sum is 28.

The square root of 2561544001 is about 50611.6982623583. The cubic root of 2561544001 is about 1368.2557233786.

Adding to 2561544001 its reverse (1004451652), we get a palindrome (3565995653).

The spelling of 2561544001 in words is "two billion, five hundred sixty-one million, five hundred forty-four thousand, one".

Divisors: 1 131 19553771 2561544001