Base | Representation |
---|---|
bin | 100101010001101111100… |
… | …001001010101111000101 |
3 | 100001220010021211001101121 |
4 | 211101233201022233011 |
5 | 313432300344132432 |
6 | 5240452101553541 |
7 | 353034415155460 |
oct | 45215741125705 |
9 | 10056107731347 |
10 | 2561671474117 |
11 | 8a8442845608 |
12 | 3545767158b1 |
13 | 15774550b862 |
14 | 8bdb25442d7 |
15 | 4697ce80197 |
hex | 2546f84abc5 |
2561671474117 has 16 divisors (see below), whose sum is σ = 3100382307072. Its totient is φ = 2066195462400.
The previous prime is 2561671474079. The next prime is 2561671474123. The reversal of 2561671474117 is 7114741761652.
2561671474117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 2561671474117 - 211 = 2561671472069 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2561671474177) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1209553 + ... + 2566390.
It is an arithmetic number, because the mean of its divisors is an integer number (193773894192).
Almost surely, 22561671474117 is an apocalyptic number.
It is an amenable number.
2561671474117 is a deficient number, since it is larger than the sum of its proper divisors (538710832955).
2561671474117 is a wasteful number, since it uses less digits than its factorization.
2561671474117 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3781668.
The product of its digits is 1975680, while the sum is 52.
The spelling of 2561671474117 in words is "two trillion, five hundred sixty-one billion, six hundred seventy-one million, four hundred seventy-four thousand, one hundred seventeen".
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