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2563960912413 = 3854653637471
BaseRepresentation
bin100101010011110111111…
…110101011101000011101
3100002010000211210120022120
4211103313332223220131
5314001442443144123
65241511204333153
7353145225110625
oct45236776535035
910063024716276
102563960912413
118a940810247a
12354ab53a41b9
13157a1b926584
148c14c623885
1546a63e672e3
hex254f7faba1d

2563960912413 has 4 divisors (see below), whose sum is σ = 3418614549888. Its totient is φ = 1709307274940.

The previous prime is 2563960912393. The next prime is 2563960912421. The reversal of 2563960912413 is 3142190693652.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2563960912413 - 217 = 2563960781341 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2563960912423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 427326818733 + ... + 427326818738.

It is an arithmetic number, because the mean of its divisors is an integer number (854653637472).

Almost surely, 22563960912413 is an apocalyptic number.

It is an amenable number.

2563960912413 is a deficient number, since it is larger than the sum of its proper divisors (854653637475).

2563960912413 is an equidigital number, since it uses as much as digits as its factorization.

2563960912413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 854653637474.

The product of its (nonzero) digits is 2099520, while the sum is 51.

The spelling of 2563960912413 in words is "two trillion, five hundred sixty-three billion, nine hundred sixty million, nine hundred twelve thousand, four hundred thirteen".

Divisors: 1 3 854653637471 2563960912413