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2564104155113 = 3597142351407
BaseRepresentation
bin100101010100000000100…
…001000110111111101001
3100002010101211100001100202
4211110000201012333221
5314002241130430423
65241533322441545
7353151614465054
oct45240041067751
910063354301322
102564104155113
118a9480a49876
12354b353632b5
13157a424ca877
148c16366da9b
1546a7180e728
hex25500846fe9

2564104155113 has 4 divisors (see below), whose sum is σ = 2571246506880. Its totient is φ = 2556961803348.

The previous prime is 2564104155089. The next prime is 2564104155121. The reversal of 2564104155113 is 3115514014652.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2564104155113 - 234 = 2546924285929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2564104155163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3571175345 + ... + 3571176062.

It is an arithmetic number, because the mean of its divisors is an integer number (642811626720).

Almost surely, 22564104155113 is an apocalyptic number.

It is an amenable number.

2564104155113 is a deficient number, since it is larger than the sum of its proper divisors (7142351767).

2564104155113 is an equidigital number, since it uses as much as digits as its factorization.

2564104155113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7142351766.

The product of its (nonzero) digits is 72000, while the sum is 38.

Adding to 2564104155113 its reverse (3115514014652), we get a palindrome (5679618169765).

The spelling of 2564104155113 in words is "two trillion, five hundred sixty-four billion, one hundred four million, one hundred fifty-five thousand, one hundred thirteen".

Divisors: 1 359 7142351407 2564104155113