Base | Representation |
---|---|
bin | 111010010111111111100110… |
… | …101010110110101101001111 |
3 | 1020200000200022012211000221112 |
4 | 322113333212222312231033 |
5 | 232122323341232042312 |
6 | 2310010402351122235 |
7 | 105035350006250132 |
oct | 7227774652665517 |
9 | 1220020265730845 |
10 | 256735540112207 |
11 | 74892a27347842 |
12 | 24965098b1337b |
13 | b034099590270 |
14 | 47580d0466219 |
15 | 1ea3431e0cd22 |
hex | e97fe6ab6b4f |
256735540112207 has 16 divisors (see below), whose sum is σ = 284044326149472. Its totient is φ = 230510679984000.
The previous prime is 256735540112203. The next prime is 256735540112299. The reversal of 256735540112207 is 702211045537652.
It is not a de Polignac number, because 256735540112207 - 22 = 256735540112203 is a prime.
It is a super-3 number, since 3×2567355401122073 (a number of 44 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (256735540112203) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80526968 + ... + 83654429.
It is an arithmetic number, because the mean of its divisors is an integer number (17752770384342).
Almost surely, 2256735540112207 is an apocalyptic number.
256735540112207 is a deficient number, since it is larger than the sum of its proper divisors (27308786037265).
256735540112207 is a wasteful number, since it uses less digits than its factorization.
256735540112207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 164184698.
The product of its (nonzero) digits is 3528000, while the sum is 50.
Adding to 256735540112207 its reverse (702211045537652), we get a palindrome (958946585649859).
The spelling of 256735540112207 in words is "two hundred fifty-six trillion, seven hundred thirty-five billion, five hundred forty million, one hundred twelve thousand, two hundred seven".
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