Base | Representation |
---|---|
bin | 10111111011101001… |
… | …110110100100101101 |
3 | 2110022212020012222120 |
4 | 113323221312210231 |
5 | 410111400423013 |
6 | 15445513303153 |
7 | 1566535645056 |
oct | 277351664455 |
9 | 73285205876 |
10 | 25696889133 |
11 | a997251163 |
12 | 4b91a04ab9 |
13 | 2566a26956 |
14 | 135ab5172d |
15 | a05e7d123 |
hex | 5fba7692d |
25696889133 has 4 divisors (see below), whose sum is σ = 34262518848. Its totient is φ = 17131259420.
The previous prime is 25696889111. The next prime is 25696889137. The reversal of 25696889133 is 33198869652.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25696889133 - 213 = 25696880941 is a prime.
It is a super-2 number, since 2×256968891332 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25696889137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4282814853 + ... + 4282814858.
It is an arithmetic number, because the mean of its divisors is an integer number (8565629712).
Almost surely, 225696889133 is an apocalyptic number.
It is an amenable number.
25696889133 is a deficient number, since it is larger than the sum of its proper divisors (8565629715).
25696889133 is an equidigital number, since it uses as much as digits as its factorization.
25696889133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8565629714.
The product of its digits is 16796160, while the sum is 60.
The spelling of 25696889133 in words is "twenty-five billion, six hundred ninety-six million, eight hundred eighty-nine thousand, one hundred thirty-three".
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