2571134034141 has 12 divisors (see below), whose sum is σ = 3875332457568. Its totient is φ = 1639563731784.

The previous prime is 2571134034067. The next prime is 2571134034151. The reversal of 2571134034141 is 1414304311752.

2571134034141 is a `hidden beast` number, since 2 + 571 + 1 + 3 + 4 + 0 + 3 + 41 + 41 = 666.

It is a de Polignac number, because none of the positive numbers 2^k-2571134034141 is a prime.

It is a super-2 number, since 2×2571134034141² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2571134034096 and 2571134034105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2571134034151) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6210468475 + ... + 6210468888.

It is an arithmetic number, because the mean of its divisors is an integer number (322944371464).

Almost surely, 2^{2571134034141} is an apocalyptic number.

It is an amenable number.

2571134034141 is a deficient number, since it is larger than the sum of its proper divisors (1304198423427).

2571134034141 is a wasteful number, since it uses less digits than its factorization.

2571134034141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12420937392 (or 12420937389 counting only the distinct ones).

The product of its (nonzero) digits is 40320, while the sum is 36.

Adding to 2571134034141 its reverse (1414304311752), we get a palindrome (3985438345893).

The spelling of 2571134034141 in words is "two trillion, five hundred seventy-one billion, one hundred thirty-four million, thirty-four thousand, one hundred forty-one".