2580394117 has 4 divisors (see below), whose sum is σ = 2949021856. Its totient is φ = 2211766380.

The previous prime is 2580394073. The next prime is 2580394133. The reversal of 2580394117 is 7114930852.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2580394117 - 2¹¹ = 2580392069 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2580394117.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2580394217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184313859 + ... + 184313872.

It is an arithmetic number, because the mean of its divisors is an integer number (737255464).

Almost surely, 2^2580394117 is an apocalyptic number.

It is an amenable number.

2580394117 is a deficient number, since it is larger than the sum of its proper divisors (368627739).

2580394117 is an equidigital number, since it uses as much as digits as its factorization.

2580394117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 368627738.

The product of its (nonzero) digits is 60480, while the sum is 40.

The square root of 2580394117 is about 50797.5798340826. The cubic root of 2580394117 is about 1371.6038043548.

The spelling of 2580394117 in words is "two billion, five hundred eighty million, three hundred ninety-four thousand, one hundred seventeen".