25928411133 has 4 divisors (see below), whose sum is σ = 34571214848. Its totient is φ = 17285607420.

The previous prime is 25928411071. The next prime is 25928411143. The reversal of 25928411133 is 33111482952.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 25928411133 - 2⁹ = 25928410621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25928411091 and 25928411100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25928411143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4321401853 + ... + 4321401858.

It is an arithmetic number, because the mean of its divisors is an integer number (8642803712).

Almost surely, 2^25928411133 is an apocalyptic number.

It is an amenable number.

25928411133 is a deficient number, since it is larger than the sum of its proper divisors (8642803715).

25928411133 is an equidigital number, since it uses as much as digits as its factorization.

25928411133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8642803714.

The product of its digits is 51840, while the sum is 39.

The spelling of 25928411133 in words is "twenty-five billion, nine hundred twenty-eight million, four hundred eleven thousand, one hundred thirty-three".