Base | Representation |
---|---|
bin | 11000001101100100… |
… | …010110001101110011 |
3 | 2111002210202120110020 |
4 | 120031210112031303 |
5 | 411220320421023 |
6 | 15535411134523 |
7 | 1610145362235 |
oct | 301544261563 |
9 | 74083676406 |
10 | 25997435763 |
11 | 10030969302 |
12 | 50565a4443 |
13 | 25b40864b0 |
14 | 1388a28255 |
15 | a22548de3 |
hex | 60d916373 |
25997435763 has 32 divisors (see below), whose sum is σ = 38533594176. Its totient is φ = 15486847488.
The previous prime is 25997435741. The next prime is 25997435803. The reversal of 25997435763 is 36753479952.
It is not a de Polignac number, because 25997435763 - 28 = 25997435507 is a prime.
It is a super-2 number, since 2×259974357632 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 25997435697 and 25997435706.
It is not an unprimeable number, because it can be changed into a prime (25997430763) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 238545 + ... + 329997.
It is an arithmetic number, because the mean of its divisors is an integer number (1204174818).
Almost surely, 225997435763 is an apocalyptic number.
25997435763 is a deficient number, since it is larger than the sum of its proper divisors (12536158413).
25997435763 is a wasteful number, since it uses less digits than its factorization.
25997435763 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91703.
The product of its digits is 42865200, while the sum is 60.
The spelling of 25997435763 in words is "twenty-five billion, nine hundred ninety-seven million, four hundred thirty-five thousand, seven hundred sixty-three".
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