Base | Representation |
---|---|
bin | 100101111101001100010… |
… | …010110000001010010001 |
3 | 100020100112122220110220112 |
4 | 211331030102300022101 |
5 | 320213322213223240 |
6 | 5314125323451105 |
7 | 356305504550510 |
oct | 45751422601221 |
9 | 10210478813815 |
10 | 2608325132945 |
11 | 9162035a1a44 |
12 | 361616986a95 |
13 | 15bc6bbc233c |
14 | 9035a674677 |
15 | 47cadb6b665 |
hex | 25f4c4b0291 |
2608325132945 has 32 divisors (see below), whose sum is σ = 3790672992000. Its totient is φ = 1683058680576.
The previous prime is 2608325132923. The next prime is 2608325132947. The reversal of 2608325132945 is 5492315238062.
2608325132945 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2608325132945 - 220 = 2608324084369 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2608325132893 and 2608325132902.
It is not an unprimeable number, because it can be changed into a prime (2608325132947) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13062974 + ... + 13261143.
It is an arithmetic number, because the mean of its divisors is an integer number (118458531000).
Almost surely, 22608325132945 is an apocalyptic number.
It is an amenable number.
2608325132945 is a deficient number, since it is larger than the sum of its proper divisors (1182347859055).
2608325132945 is a wasteful number, since it uses less digits than its factorization.
2608325132945 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26324297.
The product of its (nonzero) digits is 3110400, while the sum is 50.
The spelling of 2608325132945 in words is "two trillion, six hundred eight billion, three hundred twenty-five million, one hundred thirty-two thousand, nine hundred forty-five".
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