Base | Representation |
---|---|
bin | 1011110111110010011100… |
… | …00100110010000010010001 |
3 | 10102102201110110120120110001 |
4 | 11323321032010302002101 |
5 | 11410210314000221312 |
6 | 131304553024410001 |
7 | 5333051006016325 |
oct | 573711604620221 |
9 | 112381413516401 |
10 | 26106121101457 |
11 | 83555a885a721 |
12 | 2b1765b176901 |
13 | 1174a48340397 |
14 | 663786001985 |
15 | 304130613057 |
hex | 17be4e132091 |
26106121101457 has 4 divisors (see below), whose sum is σ = 26598689424180. Its totient is φ = 25613552778736.
The previous prime is 26106121101433. The next prime is 26106121101479. The reversal of 26106121101457 is 75410112160162.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10177433463681 + 15928687637776 = 3190209^2 + 3991076^2 .
It is a cyclic number.
It is not a de Polignac number, because 26106121101457 - 219 = 26106120577169 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (26106121101257) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 246284161282 + ... + 246284161387.
It is an arithmetic number, because the mean of its divisors is an integer number (6649672356045).
Almost surely, 226106121101457 is an apocalyptic number.
It is an amenable number.
26106121101457 is a deficient number, since it is larger than the sum of its proper divisors (492568322723).
26106121101457 is an equidigital number, since it uses as much as digits as its factorization.
26106121101457 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 492568322722.
The product of its (nonzero) digits is 20160, while the sum is 37.
The spelling of 26106121101457 in words is "twenty-six trillion, one hundred six billion, one hundred twenty-one million, one hundred one thousand, four hundred fifty-seven".
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