2623404043263 has 4 divisors (see below), whose sum is σ = 3497872057688. Its totient is φ = 1748936028840.

The previous prime is 2623404043261. The next prime is 2623404043277. The reversal of 2623404043263 is 3623404043262.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2623404043263 - 2¹ = 2623404043261 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2623404043261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 437234007208 + ... + 437234007213.

It is an arithmetic number, because the mean of its divisors is an integer number (874468014422).

Almost surely, 2^{2623404043263} is an apocalyptic number.

2623404043263 is a deficient number, since it is larger than the sum of its proper divisors (874468014425).

2623404043263 is an equidigital number, since it uses as much as digits as its factorization.

2623404043263 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 874468014424.

The product of its (nonzero) digits is 497664, while the sum is 39.

Subtracting 2623404043263 from its reverse (3623404043262), we obtain a palindrome (999999999999).

The spelling of 2623404043263 in words is "two trillion, six hundred twenty-three billion, four hundred four million, forty-three thousand, two hundred sixty-three".