26301113 has 4 divisors (see below), whose sum is σ = 27149568. Its totient is φ = 25452660.

The previous prime is 26301103. The next prime is 26301127. The reversal of 26301113 is 31110362.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31110362 = 2 ⋅15555181.

It is a cyclic number.

It is not a de Polignac number, because 26301113 - 2¹⁶ = 26235577 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 26301091 and 26301100.

It is not an unprimeable number, because it can be changed into a prime (26301103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 424181 + ... + 424242.

It is an arithmetic number, because the mean of its divisors is an integer number (6787392).

Almost surely, 2^26301113 is an apocalyptic number.

It is an amenable number.

26301113 is a deficient number, since it is larger than the sum of its proper divisors (848455).

26301113 is an equidigital number, since it uses as much as digits as its factorization.

26301113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 848454.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 26301113 is about 5128.4610752154. The cubic root of 26301113 is about 297.3888688798.

Adding to 26301113 its reverse (31110362), we get a palindrome (57411475).

Subtracting 26301113 from its reverse (31110362), we obtain a square (4809249 = 2193²).

It can be divided in two parts, 263011 and 13, that multiplied together give a palindrome (3419143).

The spelling of 26301113 in words is "twenty-six million, three hundred one thousand, one hundred thirteen".