Base | Representation |
---|---|
bin | 11000100101101000… |
… | …010101101011010011 |
3 | 2112010221101122010111 |
4 | 120211220111223103 |
5 | 413032142312230 |
6 | 20043431542151 |
7 | 1623146642662 |
oct | 304550255323 |
9 | 75127348114 |
10 | 26401135315 |
11 | 102188307a5 |
12 | 514982a957 |
13 | 26498c1979 |
14 | 13c64b2dd9 |
15 | a47bdd92a |
hex | 625a15ad3 |
26401135315 has 4 divisors (see below), whose sum is σ = 31681362384. Its totient is φ = 21120908248.
The previous prime is 26401135283. The next prime is 26401135331. The reversal of 26401135315 is 51353110462.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51353110462 = 2 ⋅25676555231.
It is a cyclic number.
It is not a de Polignac number, because 26401135315 - 25 = 26401135283 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2640113527 + ... + 2640113536.
It is an arithmetic number, because the mean of its divisors is an integer number (7920340596).
Almost surely, 226401135315 is an apocalyptic number.
26401135315 is a deficient number, since it is larger than the sum of its proper divisors (5280227069).
26401135315 is an equidigital number, since it uses as much as digits as its factorization.
26401135315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5280227068.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 26401135315 its reverse (51353110462), we get a palindrome (77754245777).
The spelling of 26401135315 in words is "twenty-six billion, four hundred one million, one hundred thirty-five thousand, three hundred fifteen".
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