Base | Representation |
---|---|
bin | 100110011010111010101… |
… | …001100100000010000011 |
3 | 100100101220221221200111220 |
4 | 212122322221210002003 |
5 | 321224203243034121 |
6 | 5340524331410123 |
7 | 361515433264101 |
oct | 46327251440203 |
9 | 10311827850456 |
10 | 2640241377411 |
11 | 9287a1476890 |
12 | 3678435b3943 |
13 | 161c87287bb1 |
14 | 91b073b4c71 |
15 | 48a2ab116c6 |
hex | 266baa64083 |
2640241377411 has 32 divisors (see below), whose sum is σ = 3850435491840. Its totient is φ = 1595946374400.
The previous prime is 2640241377407. The next prime is 2640241377461. The reversal of 2640241377411 is 1147731420462.
2640241377411 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2640241377411 - 22 = 2640241377407 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2640241377461) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 61232686 + ... + 61275788.
It is an arithmetic number, because the mean of its divisors is an integer number (120326109120).
Almost surely, 22640241377411 is an apocalyptic number.
2640241377411 is a deficient number, since it is larger than the sum of its proper divisors (1210194114429).
2640241377411 is a wasteful number, since it uses less digits than its factorization.
2640241377411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47947.
The product of its (nonzero) digits is 225792, while the sum is 42.
Adding to 2640241377411 its reverse (1147731420462), we get a palindrome (3787972797873).
The spelling of 2640241377411 in words is "two trillion, six hundred forty billion, two hundred forty-one million, three hundred seventy-seven thousand, four hundred eleven".
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