2654331121133 has 4 divisors (see below), whose sum is σ = 2654352370080. Its totient is φ = 2654309872188.

The previous prime is 2654331121129. The next prime is 2654331121153. The reversal of 2654331121133 is 3311211334562.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2654331121133 - 2² = 2654331121129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2654331121093 and 2654331121102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2654331121103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10435985 + ... + 10687302.

It is an arithmetic number, because the mean of its divisors is an integer number (663588092520).

Almost surely, 2^{2654331121133} is an apocalyptic number.

It is an amenable number.

2654331121133 is a deficient number, since it is larger than the sum of its proper divisors (21248947).

2654331121133 is a wasteful number, since it uses less digits than its factorization.

2654331121133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21248946.

The product of its digits is 38880, while the sum is 35.

Adding to 2654331121133 its reverse (3311211334562), we get a palindrome (5965542455695).

The spelling of 2654331121133 in words is "two trillion, six hundred fifty-four billion, three hundred thirty-one million, one hundred twenty-one thousand, one hundred thirty-three".