Base | Representation |
---|---|
bin | 11000111110100111… |
… | …110110010010001111 |
3 | 2120020011101101002112 |
4 | 120332213312102033 |
5 | 414412012442020 |
6 | 20153211014235 |
7 | 1636430645162 |
oct | 307647662217 |
9 | 76204341075 |
10 | 26820437135 |
11 | 1041348a428 |
12 | 524613a37b |
13 | 26b573095b |
14 | 142605dad9 |
15 | a6e9162c5 |
hex | 63e9f648f |
26820437135 has 4 divisors (see below), whose sum is σ = 32184524568. Its totient is φ = 21456349704.
The previous prime is 26820437131. The next prime is 26820437173. The reversal of 26820437135 is 53173402862.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 26820437135 - 22 = 26820437131 is a prime.
It is a super-2 number, since 2×268204371352 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 26820437092 and 26820437101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (26820437131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2682043709 + ... + 2682043718.
It is an arithmetic number, because the mean of its divisors is an integer number (8046131142).
Almost surely, 226820437135 is an apocalyptic number.
26820437135 is a deficient number, since it is larger than the sum of its proper divisors (5364087433).
26820437135 is an equidigital number, since it uses as much as digits as its factorization.
26820437135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5364087432.
The product of its (nonzero) digits is 241920, while the sum is 41.
Adding to 26820437135 its reverse (53173402862), we get a palindrome (79993839997).
The spelling of 26820437135 in words is "twenty-six billion, eight hundred twenty million, four hundred thirty-seven thousand, one hundred thirty-five".
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