Base | Representation |
---|---|
bin | 1010000010010011… |
… | …0110000111100011 |
3 | 20221202021001122111 |
4 | 2200210312013203 |
5 | 21004131412121 |
6 | 1123154020151 |
7 | 123521510335 |
oct | 24044660743 |
9 | 6852231574 |
10 | 2694013411 |
11 | 1162778171 |
12 | 632277657 |
13 | 33c19b89b |
14 | 1b7b15455 |
15 | 10b7a12e1 |
hex | a09361e3 |
2694013411 has 4 divisors (see below), whose sum is σ = 2704257072. Its totient is φ = 2683769752.
The previous prime is 2694013379. The next prime is 2694013417. The reversal of 2694013411 is 1143104962.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1143104962 = 2 ⋅571552481.
It is a cyclic number.
It is not a de Polignac number, because 2694013411 - 25 = 2694013379 is a prime.
It is a super-3 number, since 3×26940134113 (a number of 29 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2694013417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5121436 + ... + 5121961.
It is an arithmetic number, because the mean of its divisors is an integer number (676064268).
Almost surely, 22694013411 is an apocalyptic number.
2694013411 is a deficient number, since it is larger than the sum of its proper divisors (10243661).
2694013411 is a wasteful number, since it uses less digits than its factorization.
2694013411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10243660.
The product of its (nonzero) digits is 5184, while the sum is 31.
The square root of 2694013411 is about 51903.8862803162. The cubic root of 2694013411 is about 1391.4467298188.
The spelling of 2694013411 in words is "two billion, six hundred ninety-four million, thirteen thousand, four hundred eleven".
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