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27380113 = 52152553
BaseRepresentation
bin110100001110…
…0100110010001
31220112001110021
41220130212101
524002130423
62414503441
7451504255
oct150344621
956461407
1027380113
11145010a2
129204b81
135898667
1438ca265
15260c95d
hex1a1c991

27380113 has 4 divisors (see below), whose sum is σ = 27433188. Its totient is φ = 27327040.

The previous prime is 27380069. The next prime is 27380117. The reversal of 27380113 is 31108372.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 17539344 + 9840769 = 4188^2 + 3137^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-27380113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (27380117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25756 + ... + 26797.

It is an arithmetic number, because the mean of its divisors is an integer number (6858297).

Almost surely, 227380113 is an apocalyptic number.

It is an amenable number.

27380113 is a deficient number, since it is larger than the sum of its proper divisors (53075).

27380113 is an equidigital number, since it uses as much as digits as its factorization.

27380113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53074.

The product of its (nonzero) digits is 1008, while the sum is 25.

The square root of 27380113 is about 5232.6009784810. The cubic root of 27380113 is about 301.4012705382.

Adding to 27380113 its reverse (31108372), we get a palindrome (58488485).

The spelling of 27380113 in words is "twenty-seven million, three hundred eighty thousand, one hundred thirteen".

Divisors: 1 521 52553 27380113