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27900253889 = 139200721251
BaseRepresentation
bin11001111110111111…
…000001011011000001
32200000102020202012122
4121332333001123001
5424114431111024
620452303134025
72005252150034
oct317677013301
980012222178
1027900253889
1110917a69772
1254a78a4315
132828365991
1414c962701b
15ad4611d5e
hex67efc16c1

27900253889 has 4 divisors (see below), whose sum is σ = 28100975280. Its totient is φ = 27699532500.

The previous prime is 27900253883. The next prime is 27900253903. The reversal of 27900253889 is 98835200972.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-27900253889 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 27900253889.

It is not an unprimeable number, because it can be changed into a prime (27900253883) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100360487 + ... + 100360764.

It is an arithmetic number, because the mean of its divisors is an integer number (7025243820).

Almost surely, 227900253889 is an apocalyptic number.

It is an amenable number.

27900253889 is a deficient number, since it is larger than the sum of its proper divisors (200721391).

27900253889 is a wasteful number, since it uses less digits than its factorization.

27900253889 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 200721390.

The product of its (nonzero) digits is 2177280, while the sum is 53.

The spelling of 27900253889 in words is "twenty-seven billion, nine hundred million, two hundred fifty-three thousand, eight hundred eighty-nine".

Divisors: 1 139 200721251 27900253889