Base | Representation |
---|---|
bin | 11010011110110010… |
… | …010110010100100111 |
3 | 2201101121012211100121 |
4 | 122132302112110213 |
5 | 431213023140120 |
6 | 21021243022411 |
7 | 2024421222325 |
oct | 323662262447 |
9 | 81347184317 |
10 | 28433802535 |
11 | 1107115a766 |
12 | 561650aa07 |
13 | 28b1a66038 |
14 | 153a432d15 |
15 | b163a55aa |
hex | 69ec96527 |
28433802535 has 8 divisors (see below), whose sum is σ = 34128573840. Its totient is φ = 22741701504.
The previous prime is 28433802511. The next prime is 28433802541. The reversal of 28433802535 is 53520833482.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 28433802535 - 211 = 28433800487 is a prime.
It is a super-2 number, since 2×284338025352 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 28433802491 and 28433802500.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 644065 + ... + 686794.
It is an arithmetic number, because the mean of its divisors is an integer number (4266071730).
Almost surely, 228433802535 is an apocalyptic number.
28433802535 is a deficient number, since it is larger than the sum of its proper divisors (5694771305).
28433802535 is a wasteful number, since it uses less digits than its factorization.
28433802535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1335137.
The product of its (nonzero) digits is 691200, while the sum is 43.
The spelling of 28433802535 in words is "twenty-eight billion, four hundred thirty-three million, eight hundred two thousand, five hundred thirty-five".
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