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28923311437 = 171701371261
BaseRepresentation
bin11010111011111101…
…101011010101001101
32202122201022110022221
4122323331223111031
5433213331431222
621142010535341
72042514043066
oct327375532515
982581273287
1028923311437
11112a2500a79
125732437551
13295c2b6b87
14158545756d
15b4434a0c7
hex6bbf6b54d

28923311437 has 4 divisors (see below), whose sum is σ = 30624682716. Its totient is φ = 27221940160.

The previous prime is 28923311423. The next prime is 28923311441. The reversal of 28923311437 is 73411332982.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13825291561 + 15098019876 = 117581^2 + 122874^2 .

It is a cyclic number.

It is not a de Polignac number, because 28923311437 - 27 = 28923311309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 28923311393 and 28923311402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (28923311497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 850685614 + ... + 850685647.

It is an arithmetic number, because the mean of its divisors is an integer number (7656170679).

Almost surely, 228923311437 is an apocalyptic number.

It is an amenable number.

28923311437 is a deficient number, since it is larger than the sum of its proper divisors (1701371279).

28923311437 is a wasteful number, since it uses less digits than its factorization.

28923311437 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1701371278.

The product of its digits is 217728, while the sum is 43.

The spelling of 28923311437 in words is "twenty-eight billion, nine hundred twenty-three million, three hundred eleven thousand, four hundred thirty-seven".

Divisors: 1 17 1701371261 28923311437