Base | Representation |
---|---|
bin | 11011000111111110… |
… | …111010100010000011 |
3 | 2210011202202101111102 |
4 | 123013332322202003 |
5 | 434121442244220 |
6 | 21214013005015 |
7 | 2050513044632 |
oct | 330776724203 |
9 | 83152671442 |
10 | 29124962435 |
11 | 11396311398 |
12 | 5789a8376b |
13 | 2991ccb7aa |
14 | 15a4149519 |
15 | b56dcd775 |
hex | 6c7fba883 |
29124962435 has 4 divisors (see below), whose sum is σ = 34949954928. Its totient is φ = 23299969944.
The previous prime is 29124962407. The next prime is 29124962483. The reversal of 29124962435 is 53426942192.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 29124962435 - 26 = 29124962371 is a prime.
It is a super-2 number, since 2×291249624352 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 29124962435.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2912496239 + ... + 2912496248.
It is an arithmetic number, because the mean of its divisors is an integer number (8737488732).
Almost surely, 229124962435 is an apocalyptic number.
29124962435 is a deficient number, since it is larger than the sum of its proper divisors (5824992493).
29124962435 is an equidigital number, since it uses as much as digits as its factorization.
29124962435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5824992492.
The product of its digits is 933120, while the sum is 47.
The spelling of 29124962435 in words is "twenty-nine billion, one hundred twenty-four million, nine hundred sixty-two thousand, four hundred thirty-five".
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