Base | Representation |
---|---|
bin | 11011010110010011… |
… | …000001011110110111 |
3 | 2210210111122101121201 |
4 | 123112103001132313 |
5 | 440114432133212 |
6 | 21253512153331 |
7 | 2056460233420 |
oct | 332623013667 |
9 | 83714571551 |
10 | 29365114807 |
11 | 114a9929426 |
12 | 5836398847 |
13 | 29cc9a3aa2 |
14 | 15c7dc0647 |
15 | b6d019b57 |
hex | 6d64c17b7 |
29365114807 has 16 divisors (see below), whose sum is σ = 33895628800. Its totient is φ = 24918852960.
The previous prime is 29365114789. The next prime is 29365114847. The reversal of 29365114807 is 70841156392.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-29365114807 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (29365114847) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 960832 + ... + 990922.
It is an arithmetic number, because the mean of its divisors is an integer number (2118476800).
It is a 2-persistent number, because it is pandigital, and so is 2⋅29365114807 = 58730229614, but 3⋅29365114807 = 88095344421 is not.
Almost surely, 229365114807 is an apocalyptic number.
29365114807 is a deficient number, since it is larger than the sum of its proper divisors (4530513993).
29365114807 is a wasteful number, since it uses less digits than its factorization.
With its successor (29365114808) it forms an eRAP, since the sums of their prime factors are consecutive (31486 and 31487).
29365114807 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31486.
The product of its (nonzero) digits is 362880, while the sum is 46.
The spelling of 29365114807 in words is "twenty-nine billion, three hundred sixty-five million, one hundred fourteen thousand, eight hundred seven".
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