Base | Representation |
---|---|
bin | 101010110011000011001… |
… | …000000100000100010001 |
3 | 101102011022112021000020210 |
4 | 222303003020010010101 |
5 | 341141213003121033 |
6 | 10131031403354333 |
7 | 422324332406013 |
oct | 52630310040421 |
9 | 11364275230223 |
10 | 2941031301393 |
11 | a34314551719 |
12 | 3b5ba95229a9 |
13 | 18445194c333 |
14 | a24bd3bc1b3 |
15 | 51782806d63 |
hex | 2acc3204111 |
2941031301393 has 4 divisors (see below), whose sum is σ = 3921375068528. Its totient is φ = 1960687534260.
The previous prime is 2941031301371. The next prime is 2941031301419. The reversal of 2941031301393 is 3931031301492.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 2941031301393 - 25 = 2941031301361 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2941031301343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 490171883563 + ... + 490171883568.
It is an arithmetic number, because the mean of its divisors is an integer number (980343767132).
Almost surely, 22941031301393 is an apocalyptic number.
It is an amenable number.
2941031301393 is a deficient number, since it is larger than the sum of its proper divisors (980343767135).
2941031301393 is an equidigital number, since it uses as much as digits as its factorization.
2941031301393 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 980343767134.
The product of its (nonzero) digits is 52488, while the sum is 39.
Subtracting 2941031301393 from its reverse (3931031301492), we obtain a palindrome (990000000099).
The spelling of 2941031301393 in words is "two trillion, nine hundred forty-one billion, thirty-one million, three hundred one thousand, three hundred ninety-three".
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