Base | Representation |
---|---|
bin | 11100100010000010000… |
… | …10101100000001011011 |
3 | 10110201102211202100002021 |
4 | 32101001002230001123 |
5 | 112030221001022011 |
6 | 2030210321115311 |
7 | 130553555346451 |
oct | 16210102540133 |
9 | 3421384670067 |
10 | 980343767131 |
11 | 348841554243 |
12 | 139bb7188b37 |
13 | 715a4ba4111 |
14 | 3563da889d1 |
15 | 1a77aca2471 |
hex | e4410ac05b |
980343767131 has 2 divisors, whose sum is σ = 980343767132. Its totient is φ = 980343767130.
The previous prime is 980343767113. The next prime is 980343767141. The reversal of 980343767131 is 131767343089.
Together with previous prime (980343767113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 980343767131 - 25 = 980343767099 is a prime.
It is a super-2 number, since 2×9803437671312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (980343767141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 490171883565 + 490171883566.
It is an arithmetic number, because the mean of its divisors is an integer number (490171883566).
Almost surely, 2980343767131 is an apocalyptic number.
980343767131 is a deficient number, since it is larger than the sum of its proper divisors (1).
980343767131 is an equidigital number, since it uses as much as digits as its factorization.
980343767131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2286144, while the sum is 52.
The spelling of 980343767131 in words is "nine hundred eighty billion, three hundred forty-three million, seven hundred sixty-seven thousand, one hundred thirty-one".
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