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30000000000211 = 67447761194033
BaseRepresentation
bin1101101001000111010110…
…10101111110000011010011
310221012222020120200202202221
412310203223111332003103
512413010000000001321
6143445450523121511
76214266652366633
oct664435325760323
9127188216622687
1030000000000211
119616a239a122a
12344624b373297
131397cac43c387
1475a01738a6c3
1537057ecc8e41
hex1b48eb57e0d3

30000000000211 has 4 divisors (see below), whose sum is σ = 30447761194312. Its totient is φ = 29552238806112.

The previous prime is 30000000000181. The next prime is 30000000000253. The reversal of 30000000000211 is 11200000000003.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 30000000000211 - 29 = 29999999999699 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 30000000000194 and 30000000000203.

It is not an unprimeable number, because it can be changed into a prime (30000000000011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223880596950 + ... + 223880597083.

It is an arithmetic number, because the mean of its divisors is an integer number (7611940298578).

Almost surely, 230000000000211 is an apocalyptic number.

30000000000211 is a deficient number, since it is larger than the sum of its proper divisors (447761194101).

30000000000211 is an equidigital number, since it uses as much as digits as its factorization.

30000000000211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447761194100.

The product of its (nonzero) digits is 6, while the sum is 7.

Adding to 30000000000211 its reverse (11200000000003), we get a palindrome (41200000000214).

The spelling of 30000000000211 in words is "thirty trillion, two hundred eleven", and thus it is an aban number.

Divisors: 1 67 447761194033 30000000000211