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11200000000003 is a prime number
BaseRepresentation
bin1010001011111011010000…
…0001011000000000000011
31110122201011020221100210221
42202332310001120000003
52432000100000000003
635453113045403511
72234113304140333
oct242766401300003
943581136840727
1011200000000003
113628991020111
12130a775409597
13633203743219
142aa1236570c3
1514650eb2d7bd
hexa2fb4058003

11200000000003 has 2 divisors, whose sum is σ = 11200000000004. Its totient is φ = 11200000000002.

The previous prime is 11199999999959. The next prime is 11200000000051. The reversal of 11200000000003 is 30000000000211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11200000000003 - 225 = 11199966445571 is a prime.

It is not a weakly prime, because it can be changed into another prime (11200000000093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600000000001 + 5600000000002.

It is an arithmetic number, because the mean of its divisors is an integer number (5600000000002).

Almost surely, 211200000000003 is an apocalyptic number.

11200000000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

11200000000003 is an equidigital number, since it uses as much as digits as its factorization.

11200000000003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 7.

Adding to 11200000000003 its reverse (30000000000211), we get a palindrome (41200000000214).

The spelling of 11200000000003 in words is "eleven trillion, two hundred billion, three", and thus it is an aban number.