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3000001112133 = 31000000370711
BaseRepresentation
bin101011101001111110000…
…000000010100001000101
3101121210112020100210000020
4223221332000002201011
5343123000241042013
610214103111205353
7426512552465334
oct53517600024105
911553466323006
103000001112133
11a573254662a3
12405506376859
13189b8bb2c17c
14a52b5105d1b
15530848b3623
hex2ba7e002845

3000001112133 has 4 divisors (see below), whose sum is σ = 4000001482848. Its totient is φ = 2000000741420.

The previous prime is 3000001112123. The next prime is 3000001112257. The reversal of 3000001112133 is 3312111000003.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3000001112133 - 24 = 3000001112117 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3000001112123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500000185353 + ... + 500000185358.

It is an arithmetic number, because the mean of its divisors is an integer number (1000000370712).

Almost surely, 23000001112133 is an apocalyptic number.

It is an amenable number.

3000001112133 is a deficient number, since it is larger than the sum of its proper divisors (1000000370715).

3000001112133 is a wasteful number, since it uses less digits than its factorization.

3000001112133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1000000370714.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 3000001112133 its reverse (3312111000003), we get a palindrome (6312112112136).

The spelling of 3000001112133 in words is "three trillion, one million, one hundred twelve thousand, one hundred thirty-three".

Divisors: 1 3 1000000370711 3000001112133