Base | Representation |
---|---|
bin | 101011101010001010000… |
… | …011101111111101101111 |
3 | 101121211001100000122022101 |
4 | 223222022003233331233 |
5 | 343123404033130221 |
6 | 10214135135155531 |
7 | 426520560140011 |
oct | 53521203577557 |
9 | 11554040018271 |
10 | 3000203411311 |
11 | a574196796a7 |
12 | 405562075ba7 |
13 | 189bc1a0cb22 |
14 | a52d3d261b1 |
15 | 53097523d91 |
hex | 2ba8a0eff6f |
3000203411311 has 4 divisors (see below), whose sum is σ = 3000509970952. Its totient is φ = 2999896851672.
The previous prime is 3000203411297. The next prime is 3000203411339. The reversal of 3000203411311 is 1131143020003.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3000203411311 - 241 = 801180155759 is a prime.
It is a super-3 number, since 3×30002034113113 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3000203411911) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153265140 + ... + 153284713.
It is an arithmetic number, because the mean of its divisors is an integer number (750127492738).
Almost surely, 23000203411311 is an apocalyptic number.
3000203411311 is a deficient number, since it is larger than the sum of its proper divisors (306559641).
3000203411311 is an equidigital number, since it uses as much as digits as its factorization.
3000203411311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 306559640.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 3000203411311 its reverse (1131143020003), we get a palindrome (4131346431314).
The spelling of 3000203411311 in words is "three trillion, two hundred three million, four hundred eleven thousand, three hundred eleven".
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