300041204001113 has 4 divisors (see below), whose sum is σ = 306425059405440. Its totient is φ = 293657348596788.

The previous prime is 300041204001109. The next prime is 300041204001137. The reversal of 300041204001113 is 311100402140003.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 300041204001113 - 2² = 300041204001109 is a prime.

It is a super-3 number, since 3×300041204001113³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (300041204061113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3191927702093 + ... + 3191927702186.

It is an arithmetic number, because the mean of its divisors is an integer number (76606264851360).

Almost surely, 2^{300041204001113} is an apocalyptic number.

It is an amenable number.

300041204001113 is a deficient number, since it is larger than the sum of its proper divisors (6383855404327).

300041204001113 is an equidigital number, since it uses as much as digits as its factorization.

300041204001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6383855404326.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 300041204001113 its reverse (311100402140003), we get a palindrome (611141606141116).

The spelling of 300041204001113 in words is "three hundred trillion, forty-one billion, two hundred four million, one thousand, one hundred thirteen".