3000423131433 has 48 divisors (see below), whose sum is σ = 5334576374400. Its totient is φ = 1582495149312.

The previous prime is 3000423131411. The next prime is 3000423131471. The reversal of 3000423131433 is 3341313240003.

3000423131433 is a `hidden beast` number, since 300 + 0 + 4 + 2 + 313 + 1 + 43 + 3 = 666.

It is not a de Polignac number, because 3000423131433 - 2⁸ = 3000423131177 is a prime.

It is a super-3 number, since 3×3000423131433³ (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3000423131397 and 3000423131406.

It is not an unprimeable number, because it can be changed into a prime (3000423135433) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9045093 + ... + 9370941.

It is an arithmetic number, because the mean of its divisors is an integer number (111137007800).

Almost surely, 2^{3000423131433} is an apocalyptic number.

It is an amenable number.

3000423131433 is a deficient number, since it is larger than the sum of its proper divisors (2334153242967).

3000423131433 is a wasteful number, since it uses less digits than its factorization.

3000423131433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 337118 (or 337115 counting only the distinct ones).

The product of its (nonzero) digits is 7776, while the sum is 27.

Adding to 3000423131433 its reverse (3341313240003), we get a palindrome (6341736371436).

The spelling of 3000423131433 in words is "three trillion, four hundred twenty-three million, one hundred thirty-one thousand, four hundred thirty-three".