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30006560539117 = 71422627613227
BaseRepresentation
bin1101101001010011100100…
…11000011100000111101101
310221020121011210111200021101
412310221302120130013231
512413111413444222432
6143452453522203101
76214621354142341
oct664516230340755
9127217153450241
1030006560539117
119619790178208
1234475804b3491
1313987b6698566
1475a47a7cd621
15370815c374e7
hex1b4a7261c1ed

30006560539117 has 4 divisors (see below), whose sum is σ = 30429188152416. Its totient is φ = 29583932925820.

The previous prime is 30006560539093. The next prime is 30006560539147. The reversal of 30006560539117 is 71193506560003.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 30006560539117 - 231 = 30004413055469 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (30006560539147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211313806543 + ... + 211313806684.

It is an arithmetic number, because the mean of its divisors is an integer number (7607297038104).

Almost surely, 230006560539117 is an apocalyptic number.

It is an amenable number.

30006560539117 is a deficient number, since it is larger than the sum of its proper divisors (422627613299).

30006560539117 is an equidigital number, since it uses as much as digits as its factorization.

30006560539117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 422627613298.

The product of its (nonzero) digits is 510300, while the sum is 46.

The spelling of 30006560539117 in words is "thirty trillion, six billion, five hundred sixty million, five hundred thirty-nine thousand, one hundred seventeen".

Divisors: 1 71 422627613227 30006560539117