Base | Representation |
---|---|
bin | 101011110100010011101… |
… | …110110101111001101101 |
3 | 101122212011221202021010000 |
4 | 223310103232311321231 |
5 | 343313214344333010 |
6 | 10223140501534513 |
7 | 430354641141210 |
oct | 53642356657155 |
9 | 11585157667100 |
10 | 3011103121005 |
11 | a61002237941 |
12 | 4076a4414439 |
13 | 18ac3ac217a5 |
14 | a5a4976b777 |
15 | 534d43a27c0 |
hex | 2bd13bb5e6d |
3011103121005 has 40 divisors (see below), whose sum is σ = 6168778463232. Its totient is φ = 1376504282592.
The previous prime is 3011103120973. The next prime is 3011103121043. The reversal of 3011103121005 is 5001213011103.
3011103121005 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3011103121005 - 25 = 3011103120973 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 531055917 + ... + 531061586.
Almost surely, 23011103121005 is an apocalyptic number.
3011103121005 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
3011103121005 is an abundant number, since it is smaller than the sum of its proper divisors (3157675342227).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3011103121005 is a wasteful number, since it uses less digits than its factorization.
3011103121005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1062117527 (or 1062117518 counting only the distinct ones).
The product of its (nonzero) digits is 90, while the sum is 18.
Adding to 3011103121005 its reverse (5001213011103), we get a palindrome (8012316132108).
The spelling of 3011103121005 in words is "three trillion, eleven billion, one hundred three million, one hundred twenty-one thousand, five".
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