Base | Representation |
---|---|
bin | 1000110000111001101… |
… | …00100010000111110101 |
3 | 1001210021100120011210211 |
4 | 10120130310202013311 |
5 | 14413204044302041 |
6 | 350200543345421 |
7 | 30520212225016 |
oct | 4303464420765 |
9 | 1053240504724 |
10 | 301131244021 |
11 | 106788811713 |
12 | 4a4402b2271 |
13 | 225202cb87a |
14 | 1080949500d |
15 | 7c76b67481 |
hex | 461cd221f5 |
301131244021 has 4 divisors (see below), whose sum is σ = 304943032000. Its totient is φ = 297319456044.
The previous prime is 301131244003. The next prime is 301131244079. The reversal of 301131244021 is 120442131103.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 120442131103 = 7 ⋅17206018729.
It is a cyclic number.
It is not a de Polignac number, because 301131244021 - 223 = 301122855413 is a prime.
It is a super-2 number, since 2×3011312440212 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 301131243983 and 301131244001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (301131242021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1905893871 + ... + 1905894028.
It is an arithmetic number, because the mean of its divisors is an integer number (76235758000).
Almost surely, 2301131244021 is an apocalyptic number.
It is an amenable number.
301131244021 is a deficient number, since it is larger than the sum of its proper divisors (3811787979).
301131244021 is an equidigital number, since it uses as much as digits as its factorization.
301131244021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3811787978.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 301131244021 its reverse (120442131103), we get a palindrome (421573375124).
The spelling of 301131244021 in words is "three hundred one billion, one hundred thirty-one million, two hundred forty-four thousand, twenty-one".
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