Base | Representation |
---|---|
bin | 101011110100100000011… |
… | …000110101000001011001 |
3 | 101122212201202021220021112 |
4 | 223310200120311001121 |
5 | 343314133224012131 |
6 | 10223213524550105 |
7 | 430363130013026 |
oct | 53644030650131 |
9 | 11585652256245 |
10 | 3011315454041 |
11 | a61101083894 |
12 | 407743552335 |
13 | 18ac72c0653b |
14 | a5a69a4054d |
15 | 534e7d4602b |
hex | 2bd20635059 |
3011315454041 has 4 divisors (see below), whose sum is σ = 3011369581584. Its totient is φ = 3011261326500.
The previous prime is 3011315454029. The next prime is 3011315454073. The reversal of 3011315454041 is 1404545131103.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3011315454041 - 238 = 2736437547097 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3011315453989 and 3011315454007.
It is not an unprimeable number, because it can be changed into a prime (3011315454241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26980235 + ... + 27091616.
It is an arithmetic number, because the mean of its divisors is an integer number (752842395396).
Almost surely, 23011315454041 is an apocalyptic number.
It is an amenable number.
3011315454041 is a deficient number, since it is larger than the sum of its proper divisors (54127543).
3011315454041 is an equidigital number, since it uses as much as digits as its factorization.
3011315454041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54127542.
The product of its (nonzero) digits is 14400, while the sum is 32.
The spelling of 3011315454041 in words is "three trillion, eleven billion, three hundred fifteen million, four hundred fifty-four thousand, forty-one".
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