30114022000013 has 4 divisors (see below), whose sum is σ = 34416025142880. Its totient is φ = 25812018857148.

The previous prime is 30114021999973. The next prime is 30114022000063. The reversal of 30114022000013 is 31000022041103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 30114022000013 - 2¹⁰ = 30114021998989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 30114021999955 and 30114022000000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (30114022000063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2151001571423 + ... + 2151001571436.

It is an arithmetic number, because the mean of its divisors is an integer number (8604006285720).

Almost surely, 2^{30114022000013} is an apocalyptic number.

It is an amenable number.

30114022000013 is a deficient number, since it is larger than the sum of its proper divisors (4302003142867).

30114022000013 is an equidigital number, since it uses as much as digits as its factorization.

30114022000013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4302003142866.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 30114022000013 its reverse (31000022041103), we get a palindrome (61114044041116).

The spelling of 30114022000013 in words is "thirty trillion, one hundred fourteen billion, twenty-two million, thirteen", and thus it is an aban number.