Base | Representation |
---|---|
bin | 1000110000111011010… |
… | …01000111110110010011 |
3 | 1001210022022111120122221 |
4 | 10120131221013312103 |
5 | 14413221111430120 |
6 | 350202155041511 |
7 | 30520440343333 |
oct | 4303551076623 |
9 | 1053268446587 |
10 | 301145030035 |
11 | 106795578313 |
12 | 4a444a40297 |
13 | 22523117785 |
14 | 1080b2430c3 |
15 | 7c77e8c0aa |
hex | 461da47d93 |
301145030035 has 4 divisors (see below), whose sum is σ = 361374036048. Its totient is φ = 240916024024.
The previous prime is 301145030033. The next prime is 301145030063. The reversal of 301145030035 is 530030541103.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 301145030035 - 21 = 301145030033 is a prime.
It is a super-2 number, since 2×3011450300352 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 301145029991 and 301145030009.
It is not an unprimeable number, because it can be changed into a prime (301145030033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30114502999 + ... + 30114503008.
It is an arithmetic number, because the mean of its divisors is an integer number (90343509012).
Almost surely, 2301145030035 is an apocalyptic number.
301145030035 is a deficient number, since it is larger than the sum of its proper divisors (60229006013).
301145030035 is an equidigital number, since it uses as much as digits as its factorization.
301145030035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60229006012.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 301145030035 its reverse (530030541103), we get a palindrome (831175571138).
The spelling of 301145030035 in words is "three hundred one billion, one hundred forty-five million, thirty thousand, thirty-five".
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