3012113304331 has 4 divisors (see below), whose sum is σ = 3109278249664. Its totient is φ = 2914948359000.

The previous prime is 3012113304301. The next prime is 3012113304349. The reversal of 3012113304331 is 1334033112103.

3012113304331 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3012113304331 - 2³¹ = 3009965820683 is a prime.

It is a super-2 number, since 2×3012113304331² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3012113304296 and 3012113304305.

It is not an unprimeable number, because it can be changed into a prime (3012113304301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48582472620 + ... + 48582472681.

It is an arithmetic number, because the mean of its divisors is an integer number (777319562416).

Almost surely, 2^{3012113304331} is an apocalyptic number.

3012113304331 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

3012113304331 is a deficient number, since it is larger than the sum of its proper divisors (97164945333).

3012113304331 is an equidigital number, since it uses as much as digits as its factorization.

3012113304331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97164945332.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 3012113304331 its reverse (1334033112103), we get a palindrome (4346146416434).

The spelling of 3012113304331 in words is "three trillion, twelve billion, one hundred thirteen million, three hundred four thousand, three hundred thirty-one".