3012131144041 has 4 divisors (see below), whose sum is σ = 3012731055684. Its totient is φ = 3011531232400.

The previous prime is 3012131144003. The next prime is 3012131144059. The reversal of 3012131144041 is 1404411312103.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2894180110441 + 117951033600 = 1701229^2 + 343440^2 .

It is a cyclic number.

It is not a de Polignac number, because 3012131144041 - 2¹¹ = 3012131141993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3012131143997 and 3012131144015.

It is not an unprimeable number, because it can be changed into a prime (3012131154041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 299948290 + ... + 299958331.

It is an arithmetic number, because the mean of its divisors is an integer number (753182763921).

Almost surely, 2^{3012131144041} is an apocalyptic number.

It is an amenable number.

3012131144041 is a deficient number, since it is larger than the sum of its proper divisors (599911643).

3012131144041 is an equidigital number, since it uses as much as digits as its factorization.

3012131144041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 599911642.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 3012131144041 its reverse (1404411312103), we get a palindrome (4416542456144).

The spelling of 3012131144041 in words is "three trillion, twelve billion, one hundred thirty-one million, one hundred forty-four thousand, forty-one".