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30121314433 = 713731409087
BaseRepresentation
bin11100000011010111…
…101100100010000001
32212202012120022111021
4130003113230202001
5443142024030213
621500524145441
72114301643150
oct340327544201
985665508437
1030121314433
11118577733a1
125a07698281
132ac055c3a2
14165a5c7597
15bb45ddd8d
hex7035ec881

30121314433 has 8 divisors (see below), whose sum is σ = 34675633152. Its totient is φ = 25629814176.

The previous prime is 30121314413. The next prime is 30121314437. The reversal of 30121314433 is 33441312103.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 30121314433 - 25 = 30121314401 is a prime.

It is a super-2 number, since 2×301213144332 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 30121314398 and 30121314407.

It is not an unprimeable number, because it can be changed into a prime (30121314437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15703585 + ... + 15705502.

It is an arithmetic number, because the mean of its divisors is an integer number (4334454144).

Almost surely, 230121314433 is an apocalyptic number.

It is an amenable number.

30121314433 is a deficient number, since it is larger than the sum of its proper divisors (4554318719).

30121314433 is a wasteful number, since it uses less digits than its factorization.

30121314433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31409231.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 30121314433 its reverse (33441312103), we get a palindrome (63562626536).

The spelling of 30121314433 in words is "thirty billion, one hundred twenty-one million, three hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 7 137 959 31409087 219863609 4303044919 30121314433