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30134553205132 = 2261712210110699
BaseRepresentation
bin1101101101000001111110…
…10101101101100110001100
310221200211112211021210100001
412312200333111231212030
512422211031110031012
6144031342253214044
76230102214641125
oct666407725554614
9127624484253301
1030134553205132
119668aa0750632
123468340a91324
1313a78a37287ac
1476273d45104c
15373d0773a357
hex1b683f56d98c

30134553205132 has 12 divisors (see below), whose sum is σ = 52820938888200. Its totient is φ = 15042856379936.

The previous prime is 30134553205123. The next prime is 30134553205261. The reversal of 30134553205132 is 23150235543103.

It is a super-4 number, since 4×301345532051324 (a number of 55 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 30134553205091 and 30134553205100.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6105052882 + ... + 6105057817.

It is an arithmetic number, because the mean of its divisors is an integer number (4401744907350).

Almost surely, 230134553205132 is an apocalyptic number.

It is an amenable number.

30134553205132 is a deficient number, since it is larger than the sum of its proper divisors (22686385683068).

30134553205132 is a wasteful number, since it uses less digits than its factorization.

30134553205132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12210111320 (or 12210111318 counting only the distinct ones).

The product of its (nonzero) digits is 162000, while the sum is 37.

Adding to 30134553205132 its reverse (23150235543103), we get a palindrome (53284788748235).

The spelling of 30134553205132 in words is "thirty trillion, one hundred thirty-four billion, five hundred fifty-three million, two hundred five thousand, one hundred thirty-two".

Divisors: 1 2 4 617 1234 2468 12210110699 24420221398 48840442796 7533638301283 15067276602566 30134553205132