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3014043004113 = 31004681001371
BaseRepresentation
bin101011110111000010111…
…101100110110011010001
3101200010202211122210120120
4223313002331212303101
5343340230002112423
610224344321500453
7430520536552041
oct53670275466321
911603684583516
103014043004113
11a622807775a9
12408184aa1729
1318b2b9017aab
14a5c47da5721
155360751dee3
hex2bdc2f66cd1

3014043004113 has 4 divisors (see below), whose sum is σ = 4018724005488. Its totient is φ = 2009362002740.

The previous prime is 3014043004103. The next prime is 3014043004169. The reversal of 3014043004113 is 3114003404103.

3014043004113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3014043004113 - 25 = 3014043004081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3014043004103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 502340500683 + ... + 502340500688.

It is an arithmetic number, because the mean of its divisors is an integer number (1004681001372).

Almost surely, 23014043004113 is an apocalyptic number.

It is an amenable number.

3014043004113 is a deficient number, since it is larger than the sum of its proper divisors (1004681001375).

3014043004113 is a wasteful number, since it uses less digits than its factorization.

3014043004113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1004681001374.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 3014043004113 its reverse (3114003404103), we get a palindrome (6128046408216).

The spelling of 3014043004113 in words is "three trillion, fourteen billion, forty-three million, four thousand, one hundred thirteen".

Divisors: 1 3 1004681001371 3014043004113