301430234113 has 4 divisors (see below), whose sum is σ = 301896123840. Its totient is φ = 300964344388.

The previous prime is 301430234041. The next prime is 301430234117. The reversal of 301430234113 is 311432034103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 301430234113 - 2²⁵ = 301396679681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (301430234117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232943893 + ... + 232945186.

It is an arithmetic number, because the mean of its divisors is an integer number (75474030960).

Almost surely, 2^301430234113 is an apocalyptic number.

It is an amenable number.

301430234113 is a deficient number, since it is larger than the sum of its proper divisors (465889727).

301430234113 is an equidigital number, since it uses as much as digits as its factorization.

301430234113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 465889726.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 301430234113 its reverse (311432034103), we get a palindrome (612862268216).

The spelling of 301430234113 in words is "three hundred one billion, four hundred thirty million, two hundred thirty-four thousand, one hundred thirteen".